TUGAS VEKTOR
Problem 1 Find the sum of the vectors \displaystyle \overrightarrow{u}=⟨2,-1⟩ u = ⟨ 2 , − 1 ⟩ and \displaystyle \overrightarrow{v}=⟨3,5⟩ v = ⟨ 3 , 5 ⟩ Solution: \displaystyle \overrightarrow{u}+\overrightarrow{v}=⟨u_{1}+v_{1},u_{2}+v_{2}⟩=⟨2+3,-1+5⟩ u + v = ⟨ u 1 + v 1 , u 2 + v 2 ⟩ = ⟨ 2 + 3 , − 1 + 5 ⟩ \displaystyle \overrightarrow{u}+\overrightarrow{v}=⟨5,4⟩ u + v = ⟨ 5 , 4 ⟩ Problem 2 Given vectors \displaystyle \overrightarrow{u}=⟨2,-1,3⟩ u = ⟨ 2 , − 1 , 3 ⟩ \displaystyle \overrightarrow{v}=⟨3,5,0⟩ v = ⟨ 3 , 5 , 0 ⟩ \displaystyle \overrightarrow{w}=⟨-2,0,3⟩ w = ⟨ − 2 , 0 , 3 ⟩ \displaystyle \alpha =2\qquad \beta =-2\qquad \gamma =4 α = 2 β = − 2 γ = 4 Find \displaystyle \alpha \overrightarrow{u}+\beta \overrightarrow{v}+\gamma \overrightarrow{w} = α u + β v + γ w = Solution: \displaystyle \alpha \overrightarrow{u}+\beta \overrightarrow{v}+\gamma \overrightarrow{w}=2⟨2,-1,3⟩+(-2)⟨3,5,0⟩+4⟨-2,0,3...